Solve 4/5-1/3=12/15-5/15=frac{7}{15}

$$\frac { 4 } { 5 } - \frac { 1 } { 3 } = \frac { 12 } { 15 } - \frac { 5 } { 15 } = \frac { 7 } { 15 }$$

Verify

Solution Steps

Least common multiple of 5 and 3 is 15. Convert \frac{4}{5} and \frac{1}{3} to fractions with denominator 15.

$$\frac{12}{15}-\frac{5}{15}=\frac{12}{15}-\frac{5}{15}\text{ and }\frac{12}{15}-\frac{5}{15}=\frac{7}{15}$$

Since \frac{12}{15} and \frac{5}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{12-5}{15}=\frac{12}{15}-\frac{5}{15}\text{ and }\frac{12}{15}-\frac{5}{15}=\frac{7}{15}$$

Subtract 5 from 12 to get 7.

$$\frac{7}{15}=\frac{12}{15}-\frac{5}{15}\text{ and }\frac{12}{15}-\frac{5}{15}=\frac{7}{15}$$

Since \frac{12}{15} and \frac{5}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7}{15}=\frac{12-5}{15}\text{ and }\frac{12}{15}-\frac{5}{15}=\frac{7}{15}$$

Subtract 5 from 12 to get 7.

$$\frac{7}{15}=\frac{7}{15}\text{ and }\frac{12}{15}-\frac{5}{15}=\frac{7}{15}$$

Compare \frac{7}{15} and \frac{7}{15}.

$$\text{true}\text{ and }\frac{12}{15}-\frac{5}{15}=\frac{7}{15}$$

Since \frac{12}{15} and \frac{5}{15} have the same denominator, subtract them by subtracting their numerators.

$$\text{true}\text{ and }\frac{12-5}{15}=\frac{7}{15}$$

Subtract 5 from 12 to get 7.

$$\text{true}\text{ and }\frac{7}{15}=\frac{7}{15}$$

Compare \frac{7}{15} and \frac{7}{15}.

$$\text{true}\text{ and }\text{true}$$

The conjunction of \text{true} and \text{true} is \text{true}.

$$\text{true}$$