Solve 4/5div3/5div1/3-3/30

$$\frac { 4 } { 5 } \div \frac { 3 } { 5 } \div \frac { 1 } { 3 } - \frac { 3 } { 30 }$$

Evaluate

$$\frac{39}{10}=3.9$$

Solution Steps

Divide \frac{\frac{4}{5}}{\frac{3}{5}} by \frac{1}{3} by multiplying \frac{\frac{4}{5}}{\frac{3}{5}} by the reciprocal of \frac{1}{3}.

$$\frac{\frac{4}{5}\times 3}{\frac{3}{5}}-\frac{3}{30}$$

Express \frac{4}{5}\times 3 as a single fraction.

$$\frac{\frac{4\times 3}{5}}{\frac{3}{5}}-\frac{3}{30}$$

Multiply 4 and 3 to get 12.

$$\frac{\frac{12}{5}}{\frac{3}{5}}-\frac{3}{30}$$

Divide \frac{12}{5} by \frac{3}{5} by multiplying \frac{12}{5} by the reciprocal of \frac{3}{5}.

$$\frac{12}{5}\times \frac{5}{3}-\frac{3}{30}$$

Multiply \frac{12}{5} times \frac{5}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{12\times 5}{5\times 3}-\frac{3}{30}$$

Cancel out 5 in both numerator and denominator.

$$\frac{12}{3}-\frac{3}{30}$$

Divide 12 by 3 to get 4.

$$4-\frac{3}{30}$$

Reduce the fraction \frac{3}{30} to lowest terms by extracting and canceling out 3.

$$4-\frac{1}{10}$$

Convert 4 to fraction \frac{40}{10}.

$$\frac{40}{10}-\frac{1}{10}$$

Since \frac{40}{10} and \frac{1}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{40-1}{10}$$

Subtract 1 from 40 to get 39.

$$\frac{39}{10}$$

Factor

$$\frac{3 \cdot 13}{2 \cdot 5} = 3\frac{9}{10} = 3.9$$