Solve 4/5*(3+0,4)-3,2*1=

$$\frac { 4 } { 5 } \cdot ( 3 + 0,4 ) - 3,2 \cdot 1 =$$

Evaluate

$$-0,48$$

Solution Steps

Add 3 and 0,4 to get 3,4.

$$\frac{4}{5}\times 3,4-3,2\times 1$$

Convert decimal number 3,4 to fraction \frac{34}{10}. Reduce the fraction \frac{34}{10} to lowest terms by extracting and canceling out 2.

$$\frac{4}{5}\times \frac{17}{5}-3,2\times 1$$

Multiply \frac{4}{5} times \frac{17}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{4\times 17}{5\times 5}-3,2\times 1$$

Do the multiplications in the fraction \frac{4\times 17}{5\times 5}.

$$\frac{68}{25}-3,2\times 1$$

Multiply 3,2 and 1 to get 3,2.

$$\frac{68}{25}-3,2$$

Convert decimal number 3,2 to fraction \frac{32}{10}. Reduce the fraction \frac{32}{10} to lowest terms by extracting and canceling out 2.

$$\frac{68}{25}-\frac{16}{5}$$

Least common multiple of 25 and 5 is 25. Convert \frac{68}{25} and \frac{16}{5} to fractions with denominator 25.

$$\frac{68}{25}-\frac{80}{25}$$

Since \frac{68}{25} and \frac{80}{25} have the same denominator, subtract them by subtracting their numerators.

$$\frac{68-80}{25}$$

Subtract 80 from 68 to get -12.

$$-\frac{12}{25}$$

Factor

$$-0,48$$