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\frac{4}{5}+\frac{\frac{2\left(-12\right)}{3}}{-6}-\left(-3\right)^{2}||24+\left(-3\right)^{3}|\left(-5\right)|
Express \frac{2}{3}\left(-12\right) as a single fraction.
\frac{4}{5}+\frac{\frac{-24}{3}}{-6}-\left(-3\right)^{2}||24+\left(-3\right)^{3}|\left(-5\right)|
Multiply 2 and -12 to get -24.
\frac{4}{5}+\frac{-8}{-6}-\left(-3\right)^{2}||24+\left(-3\right)^{3}|\left(-5\right)|
Divide -24 by 3 to get -8.
\frac{4}{5}+\frac{4}{3}-\left(-3\right)^{2}||24+\left(-3\right)^{3}|\left(-5\right)|
Reduce the fraction \frac{-8}{-6} to lowest terms by extracting and canceling out -2.
\frac{12}{15}+\frac{20}{15}-\left(-3\right)^{2}||24+\left(-3\right)^{3}|\left(-5\right)|
Least common multiple of 5 and 3 is 15. Convert \frac{4}{5} and \frac{4}{3} to fractions with denominator 15.
\frac{12+20}{15}-\left(-3\right)^{2}||24+\left(-3\right)^{3}|\left(-5\right)|
Since \frac{12}{15} and \frac{20}{15} have the same denominator, add them by adding their numerators.
\frac{32}{15}-\left(-3\right)^{2}||24+\left(-3\right)^{3}|\left(-5\right)|
Add 12 and 20 to get 32.
\frac{32}{15}-9||24+\left(-3\right)^{3}|\left(-5\right)|
Calculate -3 to the power of 2 and get 9.
\frac{32}{15}-9||24-27|\left(-5\right)|
Calculate -3 to the power of 3 and get -27.
\frac{32}{15}-9||-3|\left(-5\right)|
Subtract 27 from 24 to get -3.
\frac{32}{15}-9|3\left(-5\right)|
The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -3 is 3.
\frac{32}{15}-9|-15|
Multiply 3 and -5 to get -15.
\frac{32}{15}-9\times 15
The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -15 is 15.
\frac{32}{15}-135
Multiply 9 and 15 to get 135.
\frac{32}{15}-\frac{2025}{15}
Convert 135 to fraction \frac{2025}{15}.
\frac{32-2025}{15}
Since \frac{32}{15} and \frac{2025}{15} have the same denominator, subtract them by subtracting their numerators.
-\frac{1993}{15}
Subtract 2025 from 32 to get -1993.