Solve 4/3z<16/19

$$\frac { 4 } { 3 } z < \frac { 16 } { 19 }$$

Solve for z

$$z<\frac{12}{19}$$

Solution Steps

Multiply both sides by \frac{3}{4}, the reciprocal of \frac{4}{3}. Since \frac{4}{3} is positive, the inequality direction remains the same.

$$z<\frac{16}{19}\times \frac{3}{4}$$

Multiply \frac{16}{19} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$z<\frac{16\times 3}{19\times 4}$$

Do the multiplications in the fraction \frac{16\times 3}{19\times 4}.

$$z<\frac{48}{76}$$

Reduce the fraction \frac{48}{76} to lowest terms by extracting and canceling out 4.

$$z<\frac{12}{19}$$