Solve 4/3x-6geq6-5x/3

$$\frac { 4 } { 3 } x - 6 \geq \frac { 6 - 5 x } { 3 }$$

Solve for x

$$x\geq \frac{8}{3}$$

Solution Steps

Multiply both sides of the equation by 3. Since 3 is positive, the inequality direction remains the same.

$$4x-18\geq 6-5x$$

Add 5x to both sides.

$$4x-18+5x\geq 6$$

Combine 4x and 5x to get 9x.

$$9x-18\geq 6$$

Add 18 to both sides.

$$9x\geq 6+18$$

Add 6 and 18 to get 24.

$$9x\geq 24$$

Divide both sides by 9. Since 9 is positive, the inequality direction remains the same.

$$x\geq \frac{24}{9}$$

Reduce the fraction \frac{24}{9} to lowest terms by extracting and canceling out 3.

$$x\geq \frac{8}{3}$$