Solve 4/3x+y=4

$$\frac { 4 } { 3 } x + y = 4$$

Solve for x

$$x=-\frac{3y}{4}+3$$

Steps for Solving Linear Equation

Subtract y from both sides.

$$\frac{4}{3}x=4-y$$

Divide both sides of the equation by \frac{4}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{4}{3}x}{\frac{4}{3}}=\frac{4-y}{\frac{4}{3}}$$

Dividing by \frac{4}{3} undoes the multiplication by \frac{4}{3}.

$$x=\frac{4-y}{\frac{4}{3}}$$

Divide 4-y by \frac{4}{3} by multiplying 4-y by the reciprocal of \frac{4}{3}.

$$x=-\frac{3y}{4}+3$$

Solve for y

$$y=-\frac{4x}{3}+4$$

Solution Steps

Subtract \frac{4}{3}x from both sides.

$$y=4-\frac{4}{3}x$$