Solve 4/3x+5<17?

$$\frac { 4 } { 3 } x + 5 < 17 ?$$

Solve for x

$$x<9$$

Solution Steps

Subtract 5 from both sides.

$$\frac{4}{3}x<17-5$$

Subtract 5 from 17 to get 12.

$$\frac{4}{3}x<12$$

Multiply both sides by \frac{3}{4}, the reciprocal of \frac{4}{3}. Since \frac{4}{3} is positive, the inequality direction remains the same.

$$x<12\times \frac{3}{4}$$

Express 12\times \frac{3}{4} as a single fraction.

$$x<\frac{12\times 3}{4}$$

Multiply 12 and 3 to get 36.

$$x<\frac{36}{4}$$

Divide 36 by 4 to get 9.

$$x<9$$