Solve 4/3x+6/3=-2/3

$$\frac { 4 } { 3 } x + \frac { 6 } { 3 } = - \frac { 2 } { 3 }$$

Solve for x

$$x=-2$$

Steps for Solving Linear Equation

Divide 6 by 3 to get 2.

$$\frac{4}{3}x+2=-\frac{2}{3}$$

Subtract 2 from both sides.

$$\frac{4}{3}x=-\frac{2}{3}-2$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{4}{3}x=-\frac{2}{3}-\frac{6}{3}$$

Since -\frac{2}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4}{3}x=\frac{-2-6}{3}$$

Subtract 6 from -2 to get -8.

$$\frac{4}{3}x=-\frac{8}{3}$$

Multiply both sides by \frac{3}{4}, the reciprocal of \frac{4}{3}.

$$x=-\frac{8}{3}\times \frac{3}{4}$$

Multiply -\frac{8}{3} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{-8\times 3}{3\times 4}$$

Cancel out 3 in both numerator and denominator.

$$x=\frac{-8}{4}$$

Divide -8 by 4 to get -2.

$$x=-2$$