Solve 4/3x+4/3=3/4x+3

$$\frac { 4 } { 3 } x + \frac { 4 } { 3 } = \frac { 3 } { 4 } x + 3$$

Solve for x

$$x = \frac{20}{7} = 2\frac{6}{7} \approx 2.857142857$$

Steps for Solving Linear Equation

Subtract \frac{3}{4}x from both sides.

$$\frac{4}{3}x+\frac{4}{3}-\frac{3}{4}x=3$$

Combine \frac{4}{3}x and -\frac{3}{4}x to get \frac{7}{12}x.

$$\frac{7}{12}x+\frac{4}{3}=3$$

Subtract \frac{4}{3} from both sides.

$$\frac{7}{12}x=3-\frac{4}{3}$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{7}{12}x=\frac{9}{3}-\frac{4}{3}$$

Since \frac{9}{3} and \frac{4}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7}{12}x=\frac{9-4}{3}$$

Subtract 4 from 9 to get 5.

$$\frac{7}{12}x=\frac{5}{3}$$

Multiply both sides by \frac{12}{7}, the reciprocal of \frac{7}{12}.

$$x=\frac{5}{3}\times \frac{12}{7}$$

Multiply \frac{5}{3} times \frac{12}{7} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{5\times 12}{3\times 7}$$

Do the multiplications in the fraction \frac{5\times 12}{3\times 7}.

$$x=\frac{60}{21}$$

Reduce the fraction \frac{60}{21} to lowest terms by extracting and canceling out 3.

$$x=\frac{20}{7}$$