Solve 4/3b+(-b)-y=1/2

$$\frac { 4 } { 3 } b + ( - b ) - y = \frac { 1 } { 2 }$$

Solve for b

$$b=3y+\frac{3}{2}$$

Steps for Solving Linear Equation

Add y to both sides.

$$\frac{4}{3}b-b=\frac{1}{2}+y$$

Combine \frac{4}{3}b and -b to get \frac{1}{3}b.

$$\frac{1}{3}b=\frac{1}{2}+y$$

The equation is in standard form.

$$\frac{1}{3}b=y+\frac{1}{2}$$

Multiply both sides by 3.

$$\frac{\frac{1}{3}b}{\frac{1}{3}}=\frac{y+\frac{1}{2}}{\frac{1}{3}}$$

Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.

$$b=\frac{y+\frac{1}{2}}{\frac{1}{3}}$$

Divide \frac{1}{2}+y by \frac{1}{3} by multiplying \frac{1}{2}+y by the reciprocal of \frac{1}{3}.

$$b=3y+\frac{3}{2}$$

Solve for y

$$y=\frac{b}{3}-\frac{1}{2}$$

Steps for Solving Linear Equation

Subtract \frac{4}{3}b from both sides.

$$-b-y=\frac{1}{2}-\frac{4}{3}b$$

Add b to both sides.

$$-y=\frac{1}{2}-\frac{4}{3}b+b$$

Combine -\frac{4}{3}b and b to get -\frac{1}{3}b.

$$-y=\frac{1}{2}-\frac{1}{3}b$$

The equation is in standard form.

$$-y=-\frac{b}{3}+\frac{1}{2}$$

Divide both sides by -1.

$$\frac{-y}{-1}=\frac{-\frac{b}{3}+\frac{1}{2}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$y=\frac{-\frac{b}{3}+\frac{1}{2}}{-1}$$

Divide \frac{1}{2}-\frac{b}{3} by -1.

$$y=\frac{b}{3}-\frac{1}{2}$$