Solve 4/3-1/6-2/9=17/18

$$\frac { 4 } { 3 } - \frac { 1 } { 6 } - \frac { 2 } { 9 } = \frac { 17 } { 18 }$$

Verify

Solution Steps

Least common multiple of 3 and 6 is 6. Convert \frac{4}{3} and \frac{1}{6} to fractions with denominator 6.

$$\frac{8}{6}-\frac{1}{6}-\frac{2}{9}=\frac{17}{18}$$

Since \frac{8}{6} and \frac{1}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{8-1}{6}-\frac{2}{9}=\frac{17}{18}$$

Subtract 1 from 8 to get 7.

$$\frac{7}{6}-\frac{2}{9}=\frac{17}{18}$$

Least common multiple of 6 and 9 is 18. Convert \frac{7}{6} and \frac{2}{9} to fractions with denominator 18.

$$\frac{21}{18}-\frac{4}{18}=\frac{17}{18}$$

Since \frac{21}{18} and \frac{4}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{21-4}{18}=\frac{17}{18}$$

Subtract 4 from 21 to get 17.

$$\frac{17}{18}=\frac{17}{18}$$

Compare \frac{17}{18} and \frac{17}{18}.

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