Solve 4/3*4/3+4/3+4/3=frac{4}{3}*3

$$\frac { 4 } { 3 } \times \frac { 4 } { 3 } + \frac { 4 } { 3 } + \frac { 4 } { 3 } = \frac { 4 } { 3 } \cdot 3$$

Verify

Solution Steps

Multiply \frac{4}{3} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{4\times 4}{3\times 3}+\frac{4}{3}+\frac{4}{3}=\frac{4}{3}\times 3$$

Do the multiplications in the fraction \frac{4\times 4}{3\times 3}.

$$\frac{16}{9}+\frac{4}{3}+\frac{4}{3}=\frac{4}{3}\times 3$$

Least common multiple of 9 and 3 is 9. Convert \frac{16}{9} and \frac{4}{3} to fractions with denominator 9.

$$\frac{16}{9}+\frac{12}{9}+\frac{4}{3}=\frac{4}{3}\times 3$$

Since \frac{16}{9} and \frac{12}{9} have the same denominator, add them by adding their numerators.

$$\frac{16+12}{9}+\frac{4}{3}=\frac{4}{3}\times 3$$

Add 16 and 12 to get 28.

$$\frac{28}{9}+\frac{4}{3}=\frac{4}{3}\times 3$$

Least common multiple of 9 and 3 is 9. Convert \frac{28}{9} and \frac{4}{3} to fractions with denominator 9.

$$\frac{28}{9}+\frac{12}{9}=\frac{4}{3}\times 3$$

Since \frac{28}{9} and \frac{12}{9} have the same denominator, add them by adding their numerators.

$$\frac{28+12}{9}=\frac{4}{3}\times 3$$

Add 28 and 12 to get 40.

$$\frac{40}{9}=\frac{4}{3}\times 3$$

Cancel out 3 and 3.

$$\frac{40}{9}=4$$

Convert 4 to fraction \frac{36}{9}.

$$\frac{40}{9}=\frac{36}{9}$$

Compare \frac{40}{9} and \frac{36}{9}.

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