Solve 4/3+3/4+1/4=

$$\frac { 4 } { 3 } + \frac { 3 } { 4 } + \frac { 1 } { 4 } =$$

Evaluate

$$\frac{7}{3}\approx 2.333333333$$

Solution Steps

Least common multiple of 3 and 4 is 12. Convert \frac{4}{3} and \frac{3}{4} to fractions with denominator 12.

$$\frac{16}{12}+\frac{9}{12}+\frac{1}{4}$$

Since \frac{16}{12} and \frac{9}{12} have the same denominator, add them by adding their numerators.

$$\frac{16+9}{12}+\frac{1}{4}$$

Add 16 and 9 to get 25.

$$\frac{25}{12}+\frac{1}{4}$$

Least common multiple of 12 and 4 is 12. Convert \frac{25}{12} and \frac{1}{4} to fractions with denominator 12.

$$\frac{25}{12}+\frac{3}{12}$$

Since \frac{25}{12} and \frac{3}{12} have the same denominator, add them by adding their numerators.

$$\frac{25+3}{12}$$

Add 25 and 3 to get 28.

$$\frac{28}{12}$$

Reduce the fraction \frac{28}{12} to lowest terms by extracting and canceling out 4.

$$\frac{7}{3}$$

Factor

$$\frac{7}{3} = 2\frac{1}{3} = 2.3333333333333335$$