Solve 4/3+3/2v=-1/2

$$\frac { 4 } { 3 } + \frac { 3 } { 2 } v = - \frac { 1 } { 2 }$$

Solve for v

$$v = -\frac{11}{9} = -1\frac{2}{9} \approx -1.222222222$$

Steps for Solving Linear Equation

Subtract \frac{4}{3} from both sides.

$$\frac{3}{2}v=-\frac{1}{2}-\frac{4}{3}$$

Least common multiple of 2 and 3 is 6. Convert -\frac{1}{2} and \frac{4}{3} to fractions with denominator 6.

$$\frac{3}{2}v=-\frac{3}{6}-\frac{8}{6}$$

Since -\frac{3}{6} and \frac{8}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3}{2}v=\frac{-3-8}{6}$$

Subtract 8 from -3 to get -11.

$$\frac{3}{2}v=-\frac{11}{6}$$

Multiply both sides by \frac{2}{3}, the reciprocal of \frac{3}{2}.

$$v=-\frac{11}{6}\times \frac{2}{3}$$

Multiply -\frac{11}{6} times \frac{2}{3} by multiplying numerator times numerator and denominator times denominator.

$$v=\frac{-11\times 2}{6\times 3}$$

Do the multiplications in the fraction \frac{-11\times 2}{6\times 3}.

$$v=\frac{-22}{18}$$

Reduce the fraction \frac{-22}{18} to lowest terms by extracting and canceling out 2.

$$v=-\frac{11}{9}$$