Solve 4/3+1^2{5+frac{3^2/3^2}}

$$\frac { 4 } { 3 + \frac { 1 ^ { 2 } } { 5 + \frac { 3 ^ { 2 } } { 3 ^ { 2 } } } }$$

Evaluate

$$\frac{24}{19}\approx 1.263157895$$

Solution Steps

Divide 3^{2} by 3^{2} to get 1.

$$\frac{4}{3+\frac{1^{2}}{5+1}}$$

Calculate 1 to the power of 2 and get 1.

$$\frac{4}{3+\frac{1}{5+1}}$$

Add 5 and 1 to get 6.

$$\frac{4}{3+\frac{1}{6}}$$

Convert 3 to fraction \frac{18}{6}.

$$\frac{4}{\frac{18}{6}+\frac{1}{6}}$$

Since \frac{18}{6} and \frac{1}{6} have the same denominator, add them by adding their numerators.

$$\frac{4}{\frac{18+1}{6}}$$

Add 18 and 1 to get 19.

$$\frac{4}{\frac{19}{6}}$$

Divide 4 by \frac{19}{6} by multiplying 4 by the reciprocal of \frac{19}{6}.

$$4\times \frac{6}{19}$$

Express 4\times \frac{6}{19} as a single fraction.

$$\frac{4\times 6}{19}$$

Multiply 4 and 6 to get 24.

$$\frac{24}{19}$$

Factor

$$\frac{2 ^ {3} \cdot 3}{19} = 1\frac{5}{19} = 1.263157894736842$$