Solve 4/23b=b/x

$$\frac { 4 } { 23 b } = \frac { b } { x }$$

Solve for x

$$x=\frac{23b^{2}}{4}$$

$$b\neq 0$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 23bx, the least common multiple of 23b,x.

$$x\times 4=23bb$$

Multiply b and b to get b^{2}.

$$x\times 4=23b^{2}$$

The equation is in standard form.

$$4x=23b^{2}$$

Divide both sides by 4.

$$\frac{4x}{4}=\frac{23b^{2}}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$x=\frac{23b^{2}}{4}$$

Variable x cannot be equal to 0.

$$x=\frac{23b^{2}}{4}\text{, }x\neq 0$$

Solve for b (complex solution)

$$b=-\frac{2\sqrt{23x}}{23}$$

$$b=\frac{2\sqrt{23x}}{23}\text{, }x\neq 0$$

Solve for b

$$b=\frac{2\sqrt{23x}}{23}$$

$$b=-\frac{2\sqrt{23x}}{23}\text{, }x>0$$