Solve 4/2^2-3+10/40^2-9=1/20+3

$$\frac { 4 } { 2 ^ { 2 } - 3 } + \frac { 10 } { 40 ^ { 2 } - 9 } = \frac { 1 } { 20 + 3 }$$

Verify

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\frac{4}{4-3}+\frac{10}{40^{2}-9}=\frac{1}{20+3}$$

Subtract 3 from 4 to get 1.

$$\frac{4}{1}+\frac{10}{40^{2}-9}=\frac{1}{20+3}$$

Anything divided by one gives itself.

$$4+\frac{10}{40^{2}-9}=\frac{1}{20+3}$$

Calculate 40 to the power of 2 and get 1600.

$$4+\frac{10}{1600-9}=\frac{1}{20+3}$$

Subtract 9 from 1600 to get 1591.

$$4+\frac{10}{1591}=\frac{1}{20+3}$$

Convert 4 to fraction \frac{6364}{1591}.

$$\frac{6364}{1591}+\frac{10}{1591}=\frac{1}{20+3}$$

Since \frac{6364}{1591} and \frac{10}{1591} have the same denominator, add them by adding their numerators.

$$\frac{6364+10}{1591}=\frac{1}{20+3}$$

Add 6364 and 10 to get 6374.

$$\frac{6374}{1591}=\frac{1}{20+3}$$

Add 20 and 3 to get 23.

$$\frac{6374}{1591}=\frac{1}{23}$$

Least common multiple of 1591 and 23 is 36593. Convert \frac{6374}{1591} and \frac{1}{23} to fractions with denominator 36593.

$$\frac{146602}{36593}=\frac{1591}{36593}$$

Compare \frac{146602}{36593} and \frac{1591}{36593}.

$$\text{false}$$