Solve 4/12div8/1=6/12*1/8=frac{4}{96}

$$\frac { 4 } { 12 } \div \frac { 8 } { 1 } = \frac { 6 } { 12 } \times \frac { 1 } { 8 } = \frac { 4 } { 96 }$$

Verify

Solution Steps

Divide \frac{4}{12} by \frac{8}{1} by multiplying \frac{4}{12} by the reciprocal of \frac{8}{1}.

$$\frac{4}{12\times 8}=\frac{6}{12}\times \frac{1}{8}\text{ and }\frac{6}{12}\times \frac{1}{8}=\frac{4}{96}$$

Multiply 12 and 8 to get 96.

$$\frac{4}{96}=\frac{6}{12}\times \frac{1}{8}\text{ and }\frac{6}{12}\times \frac{1}{8}=\frac{4}{96}$$

Reduce the fraction \frac{4}{96} to lowest terms by extracting and canceling out 4.

$$\frac{1}{24}=\frac{6}{12}\times \frac{1}{8}\text{ and }\frac{6}{12}\times \frac{1}{8}=\frac{4}{96}$$

Reduce the fraction \frac{6}{12} to lowest terms by extracting and canceling out 6.

$$\frac{1}{24}=\frac{1}{2}\times \frac{1}{8}\text{ and }\frac{6}{12}\times \frac{1}{8}=\frac{4}{96}$$

Multiply \frac{1}{2} times \frac{1}{8} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1}{24}=\frac{1\times 1}{2\times 8}\text{ and }\frac{6}{12}\times \frac{1}{8}=\frac{4}{96}$$

Do the multiplications in the fraction \frac{1\times 1}{2\times 8}.

$$\frac{1}{24}=\frac{1}{16}\text{ and }\frac{6}{12}\times \frac{1}{8}=\frac{4}{96}$$

Least common multiple of 24 and 16 is 48. Convert \frac{1}{24} and \frac{1}{16} to fractions with denominator 48.

$$\frac{2}{48}=\frac{3}{48}\text{ and }\frac{6}{12}\times \frac{1}{8}=\frac{4}{96}$$

Compare \frac{2}{48} and \frac{3}{48}.

$$\text{false}\text{ and }\frac{6}{12}\times \frac{1}{8}=\frac{4}{96}$$

Reduce the fraction \frac{6}{12} to lowest terms by extracting and canceling out 6.

$$\text{false}\text{ and }\frac{1}{2}\times \frac{1}{8}=\frac{4}{96}$$

Multiply \frac{1}{2} times \frac{1}{8} by multiplying numerator times numerator and denominator times denominator.

$$\text{false}\text{ and }\frac{1\times 1}{2\times 8}=\frac{4}{96}$$

Do the multiplications in the fraction \frac{1\times 1}{2\times 8}.

$$\text{false}\text{ and }\frac{1}{16}=\frac{4}{96}$$

Reduce the fraction \frac{4}{96} to lowest terms by extracting and canceling out 4.

$$\text{false}\text{ and }\frac{1}{16}=\frac{1}{24}$$

Least common multiple of 16 and 24 is 48. Convert \frac{1}{16} and \frac{1}{24} to fractions with denominator 48.

$$\text{false}\text{ and }\frac{3}{48}=\frac{2}{48}$$

Compare \frac{3}{48} and \frac{2}{48}.

$$\text{false}\text{ and }\text{false}$$

The conjunction of \text{false} and \text{false} is \text{false}.

$$\text{false}$$