Solve 4/12*5/15*60/20*24-3/9*frac{18}{2}*40

$$\frac { 4 } { 12 } \cdot \frac { 5 } { 15 } \cdot \frac { 60 } { 20 } \cdot 24 - \frac { 3 } { 9 } \cdot \frac { 18 } { 2 } \cdot 40$$

Evaluate

$$-112$$

Solution Steps

Reduce the fraction \frac{4}{12} to lowest terms by extracting and canceling out 4.

$$\frac{1}{3}\times \frac{5}{15}\times \frac{60}{20}\times 24-\frac{3}{9}\times \frac{18}{2}\times 40$$

Reduce the fraction \frac{5}{15} to lowest terms by extracting and canceling out 5.

$$\frac{1}{3}\times \frac{1}{3}\times \frac{60}{20}\times 24-\frac{3}{9}\times \frac{18}{2}\times 40$$

Multiply \frac{1}{3} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 1}{3\times 3}\times \frac{60}{20}\times 24-\frac{3}{9}\times \frac{18}{2}\times 40$$

Do the multiplications in the fraction \frac{1\times 1}{3\times 3}.

$$\frac{1}{9}\times \frac{60}{20}\times 24-\frac{3}{9}\times \frac{18}{2}\times 40$$

Divide 60 by 20 to get 3.

$$\frac{1}{9}\times 3\times 24-\frac{3}{9}\times \frac{18}{2}\times 40$$

Multiply \frac{1}{9} and 3 to get \frac{3}{9}.

$$\frac{3}{9}\times 24-\frac{3}{9}\times \frac{18}{2}\times 40$$

Reduce the fraction \frac{3}{9} to lowest terms by extracting and canceling out 3.

$$\frac{1}{3}\times 24-\frac{3}{9}\times \frac{18}{2}\times 40$$

Multiply \frac{1}{3} and 24 to get \frac{24}{3}.

$$\frac{24}{3}-\frac{3}{9}\times \frac{18}{2}\times 40$$

Divide 24 by 3 to get 8.

$$8-\frac{3}{9}\times \frac{18}{2}\times 40$$

Reduce the fraction \frac{3}{9} to lowest terms by extracting and canceling out 3.

$$8-\frac{1}{3}\times \frac{18}{2}\times 40$$

Divide 18 by 2 to get 9.

$$8-\frac{1}{3}\times 9\times 40$$

Multiply \frac{1}{3} and 9 to get \frac{9}{3}.

$$8-\frac{9}{3}\times 40$$

Divide 9 by 3 to get 3.

$$8-3\times 40$$

Multiply 3 and 40 to get 120.

$$8-120$$

Subtract 120 from 8 to get -112.

$$-112$$

Factor

$$-112$$