Solve 4/103+3/96

$$\frac { 4 } { 103 } + \frac { 3 } { 96 }$$

Evaluate

$$\frac{231}{3296}\approx 0.070084951$$

Solution Steps

Reduce the fraction \frac{3}{96} to lowest terms by extracting and canceling out 3.

$$\frac{4}{103}+\frac{1}{32}$$

Least common multiple of 103 and 32 is 3296. Convert \frac{4}{103} and \frac{1}{32} to fractions with denominator 3296.

$$\frac{128}{3296}+\frac{103}{3296}$$

Since \frac{128}{3296} and \frac{103}{3296} have the same denominator, add them by adding their numerators.

$$\frac{128+103}{3296}$$

Add 128 and 103 to get 231.

$$\frac{231}{3296}$$

Factor

$$\frac{3 \cdot 7 \cdot 11}{2 ^ {5} \cdot 103} = 0.07008495145631068$$