Solve 4*3*7+4*5*6*2+5*4*5/9*8*(4+5+2)

$$\frac { 4 \times 3 \times 7 + 4 \times 5 \times 6 \times 2 + 5 \times 4 \times 5 } { 9 \times 8 \times ( 4 + 5 + 2 ) }$$

Evaluate

$$\frac{53}{99}\approx 0.535353535$$

Solution Steps

Multiply 4 and 3 to get 12. Multiply 4 and 5 to get 20. Multiply 5 and 4 to get 20.

$$\frac{12\times 7+20\times 6\times 2+20\times 5}{9\times 8\left(4+5+2\right)}$$

Multiply 12 and 7 to get 84.

$$\frac{84+20\times 6\times 2+20\times 5}{9\times 8\left(4+5+2\right)}$$

Multiply 20 and 6 to get 120.

$$\frac{84+120\times 2+20\times 5}{9\times 8\left(4+5+2\right)}$$

Multiply 120 and 2 to get 240.

$$\frac{84+240+20\times 5}{9\times 8\left(4+5+2\right)}$$

Add 84 and 240 to get 324.

$$\frac{324+20\times 5}{9\times 8\left(4+5+2\right)}$$

Multiply 20 and 5 to get 100.

$$\frac{324+100}{9\times 8\left(4+5+2\right)}$$

Add 324 and 100 to get 424.

$$\frac{424}{9\times 8\left(4+5+2\right)}$$

Multiply 9 and 8 to get 72.

$$\frac{424}{72\left(4+5+2\right)}$$

Add 4 and 5 to get 9.

$$\frac{424}{72\left(9+2\right)}$$

Add 9 and 2 to get 11.

$$\frac{424}{72\times 11}$$

Multiply 72 and 11 to get 792.

$$\frac{424}{792}$$

Reduce the fraction \frac{424}{792} to lowest terms by extracting and canceling out 8.

$$\frac{53}{99}$$

Factor

$$\frac{53}{3 ^ {2} \cdot 11} = 0.5353535353535354$$