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\frac{\left(4\sqrt{3}+3\sqrt{6}\right)\sqrt{3}}{2\left(\sqrt{3}\right)^{2}}
Rationalize the denominator of \frac{4\sqrt{3}+3\sqrt{6}}{2\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\frac{\left(4\sqrt{3}+3\sqrt{6}\right)\sqrt{3}}{2\times 3}
The square of \sqrt{3} is 3.
\frac{\left(4\sqrt{3}+3\sqrt{6}\right)\sqrt{3}}{6}
Multiply 2 and 3 to get 6.
\frac{4\left(\sqrt{3}\right)^{2}+3\sqrt{6}\sqrt{3}}{6}
Use the distributive property to multiply 4\sqrt{3}+3\sqrt{6} by \sqrt{3}.
\frac{4\times 3+3\sqrt{6}\sqrt{3}}{6}
The square of \sqrt{3} is 3.
\frac{12+3\sqrt{6}\sqrt{3}}{6}
Multiply 4 and 3 to get 12.
\frac{12+3\sqrt{3}\sqrt{2}\sqrt{3}}{6}
Factor 6=3\times 2. Rewrite the square root of the product \sqrt{3\times 2} as the product of square roots \sqrt{3}\sqrt{2}.
\frac{12+3\times 3\sqrt{2}}{6}
Multiply \sqrt{3} and \sqrt{3} to get 3.
\frac{12+9\sqrt{2}}{6}
Multiply 3 and 3 to get 9.