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\frac{4\times 2\sqrt{3}}{9\sqrt{6}}
Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.
\frac{8\sqrt{3}}{9\sqrt{6}}
Multiply 4 and 2 to get 8.
\frac{8\sqrt{3}\sqrt{6}}{9\left(\sqrt{6}\right)^{2}}
Rationalize the denominator of \frac{8\sqrt{3}}{9\sqrt{6}} by multiplying numerator and denominator by \sqrt{6}.
\frac{8\sqrt{3}\sqrt{6}}{9\times 6}
The square of \sqrt{6} is 6.
\frac{8\sqrt{3}\sqrt{3}\sqrt{2}}{9\times 6}
Factor 6=3\times 2. Rewrite the square root of the product \sqrt{3\times 2} as the product of square roots \sqrt{3}\sqrt{2}.
\frac{8\times 3\sqrt{2}}{9\times 6}
Multiply \sqrt{3} and \sqrt{3} to get 3.
\frac{8\times 3\sqrt{2}}{54}
Multiply 9 and 6 to get 54.
\frac{24\sqrt{2}}{54}
Multiply 8 and 3 to get 24.
\frac{4}{9}\sqrt{2}
Divide 24\sqrt{2} by 54 to get \frac{4}{9}\sqrt{2}.