Solve 4*2^8-2^7/3*2^7+2^9

$$\frac { 4 \cdot 2 ^ { 8 } - 2 ^ { 7 } } { 3 \cdot 2 ^ { 7 } + 2 ^ { 9 } }$$

Evaluate

$$1$$

Solution Steps

Calculate 2 to the power of 8 and get 256.

$$\frac{4\times 256-2^{7}}{3\times 2^{7}+2^{9}}$$

Multiply 4 and 256 to get 1024.

$$\frac{1024-2^{7}}{3\times 2^{7}+2^{9}}$$

Calculate 2 to the power of 7 and get 128.

$$\frac{1024-128}{3\times 2^{7}+2^{9}}$$

Subtract 128 from 1024 to get 896.

$$\frac{896}{3\times 2^{7}+2^{9}}$$

Calculate 2 to the power of 7 and get 128.

$$\frac{896}{3\times 128+2^{9}}$$

Multiply 3 and 128 to get 384.

$$\frac{896}{384+2^{9}}$$

Calculate 2 to the power of 9 and get 512.

$$\frac{896}{384+512}$$

Add 384 and 512 to get 896.

$$\frac{896}{896}$$

Divide 896 by 896 to get 1.

$$1$$

Factor

$$1$$