Solve frac{4^{2}*3^2*6^3}{4^4*9^2}

$$\frac { 4 ^ { 2 } \times 3 ^ { 2 } \times 6 ^ { 3 } } { 4 ^ { 4 } \times 9 ^ { 2 } }$$

Evaluate

$$\frac{3}{2}=1.5$$

Solution Steps

Cancel out 4^{2} in both numerator and denominator.

$$\frac{3^{2}\times 6^{3}}{4^{2}\times 9^{2}}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{9\times 6^{3}}{4^{2}\times 9^{2}}$$

Calculate 6 to the power of 3 and get 216.

$$\frac{9\times 216}{4^{2}\times 9^{2}}$$

Multiply 9 and 216 to get 1944.

$$\frac{1944}{4^{2}\times 9^{2}}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{1944}{16\times 9^{2}}$$

Calculate 9 to the power of 2 and get 81.

$$\frac{1944}{16\times 81}$$

Multiply 16 and 81 to get 1296.

$$\frac{1944}{1296}$$

Reduce the fraction \frac{1944}{1296} to lowest terms by extracting and canceling out 648.

$$\frac{3}{2}$$

Factor

$$\frac{3}{2} = 1\frac{1}{2} = 1.5$$