Solve frac{4^2*16^frac{1{2}}}{64^frac{2{3}}*4^3}

$$\frac { 4 ^ { 2 } \times 16 ^ { \frac { 1 } { 2 } } } { 64 ^ { \frac { 2 } { 3 } } \times 4 ^ { 3 } }$$

Evaluate

$$\frac{1}{16}=0.0625$$

Solution Steps

Cancel out 4^{2} in both numerator and denominator.

$$\frac{\sqrt{16}}{4\times 64^{\frac{2}{3}}}$$

Calculate the square root of 16 and get 4.

$$\frac{4}{4\times 64^{\frac{2}{3}}}$$

Calculate 64 to the power of \frac{2}{3} and get 16.

$$\frac{4}{4\times 16}$$

Multiply 4 and 16 to get 64.

$$\frac{4}{64}$$

Reduce the fraction \frac{4}{64} to lowest terms by extracting and canceling out 4.

$$\frac{1}{16}$$

Factor

$$\frac{1}{2 ^ {4}} = 0.0625$$