Solve 4^2:2^3/2^3-4=

$$\frac { 4 ^ { 2 } : 2 ^ { 3 } } { 2 ^ { 3 } } - 4 =$$

Evaluate

$$-\frac{15}{4}=-3.75$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$\frac{\frac{16}{2^{3}}}{2^{3}}-4$$

Calculate 2 to the power of 3 and get 8.

$$\frac{\frac{16}{8}}{2^{3}}-4$$

Divide 16 by 8 to get 2.

$$\frac{2}{2^{3}}-4$$

Calculate 2 to the power of 3 and get 8.

$$\frac{2}{8}-4$$

Reduce the fraction \frac{2}{8} to lowest terms by extracting and canceling out 2.

$$\frac{1}{4}-4$$

Convert 4 to fraction \frac{16}{4}.

$$\frac{1}{4}-\frac{16}{4}$$

Since \frac{1}{4} and \frac{16}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-16}{4}$$

Subtract 16 from 1 to get -15.

$$-\frac{15}{4}$$

Factor

$$-\frac{15}{4} = -3\frac{3}{4} = -3.75$$