Solve frac{4^{-2}x^{2}c^-1}{3^-3c^-1b^2}=

$$\frac { 4 ^ { - 2 } x ^ { 2 } c ^ { - 1 } } { 3 ^ { - 3 } c ^ { - 1 } b ^ { 2 } } =$$

Evaluate

$$\frac{27\times \left(\frac{x}{b}\right)^{2}}{16}$$

Solution Steps

Cancel out \frac{1}{c} in both numerator and denominator.

$$\frac{4^{-2}x^{2}}{3^{-3}b^{2}}$$

Calculate 4 to the power of -2 and get \frac{1}{16}.

$$\frac{\frac{1}{16}x^{2}}{3^{-3}b^{2}}$$

Calculate 3 to the power of -3 and get \frac{1}{27}.

$$\frac{\frac{1}{16}x^{2}}{\frac{1}{27}b^{2}}$$

Differentiate w.r.t. x

$$\frac{27x}{8b^{2}}$$