Solve 4^-1+2^-2/2^3

$$\frac { 4 ^ { - 1 } + 2 ^ { - 2 } } { 2 ^ { 3 } }$$

Evaluate

$$\frac{1}{16}=0.0625$$

Solution Steps

Calculate 4 to the power of -1 and get \frac{1}{4}.

$$\frac{\frac{1}{4}+2^{-2}}{2^{3}}$$

Calculate 2 to the power of -2 and get \frac{1}{4}.

$$\frac{\frac{1}{4}+\frac{1}{4}}{2^{3}}$$

Add \frac{1}{4} and \frac{1}{4} to get \frac{1}{2}.

$$\frac{\frac{1}{2}}{2^{3}}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{\frac{1}{2}}{8}$$

Express \frac{\frac{1}{2}}{8} as a single fraction.

$$\frac{1}{2\times 8}$$

Multiply 2 and 8 to get 16.

$$\frac{1}{16}$$

Factor

$$\frac{1}{2 ^ {4}} = 0.0625$$