Solve 4+p/5(-2)=-1

$$\frac { 4 + p } { 5 ( - 2 ) } = - 1$$

Solve for p

$$p=6$$

Steps for Solving Linear Equation

Multiply 5 and -2 to get -10.

$$\frac{4+p}{-10}=-1$$

Multiply both numerator and denominator by -1.

$$\frac{-4-p}{10}=-1$$

Divide each term of -4-p by 10 to get -\frac{2}{5}-\frac{1}{10}p.

$$-\frac{2}{5}-\frac{1}{10}p=-1$$

Add \frac{2}{5} to both sides.

$$-\frac{1}{10}p=-1+\frac{2}{5}$$

Convert -1 to fraction -\frac{5}{5}.

$$-\frac{1}{10}p=-\frac{5}{5}+\frac{2}{5}$$

Since -\frac{5}{5} and \frac{2}{5} have the same denominator, add them by adding their numerators.

$$-\frac{1}{10}p=\frac{-5+2}{5}$$

Add -5 and 2 to get -3.

$$-\frac{1}{10}p=-\frac{3}{5}$$

Multiply both sides by -10, the reciprocal of -\frac{1}{10}.

$$p=-\frac{3}{5}\left(-10\right)$$

Express -\frac{3}{5}\left(-10\right) as a single fraction.

$$p=\frac{-3\left(-10\right)}{5}$$

Multiply -3 and -10 to get 30.

$$p=\frac{30}{5}$$

Divide 30 by 5 to get 6.

$$p=6$$