Solve 4+7/9/5-frac{3{4}}

$$\frac { 4 + \frac { 7 } { 9 } } { 5 - \frac { 3 } { 4 } }$$

Evaluate

$$\frac{172}{153}\approx 1.124183007$$

Solution Steps

Convert 4 to fraction \frac{36}{9}.

$$\frac{\frac{36}{9}+\frac{7}{9}}{5-\frac{3}{4}}$$

Since \frac{36}{9} and \frac{7}{9} have the same denominator, add them by adding their numerators.

$$\frac{\frac{36+7}{9}}{5-\frac{3}{4}}$$

Add 36 and 7 to get 43.

$$\frac{\frac{43}{9}}{5-\frac{3}{4}}$$

Convert 5 to fraction \frac{20}{4}.

$$\frac{\frac{43}{9}}{\frac{20}{4}-\frac{3}{4}}$$

Since \frac{20}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{43}{9}}{\frac{20-3}{4}}$$

Subtract 3 from 20 to get 17.

$$\frac{\frac{43}{9}}{\frac{17}{4}}$$

Divide \frac{43}{9} by \frac{17}{4} by multiplying \frac{43}{9} by the reciprocal of \frac{17}{4}.

$$\frac{43}{9}\times \frac{4}{17}$$

Multiply \frac{43}{9} times \frac{4}{17} by multiplying numerator times numerator and denominator times denominator.

$$\frac{43\times 4}{9\times 17}$$

Do the multiplications in the fraction \frac{43\times 4}{9\times 17}.

$$\frac{172}{153}$$

Factor

$$\frac{2 ^ {2} \cdot 43}{3 ^ {2} \cdot 17} = 1\frac{19}{153} = 1.1241830065359477$$