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\frac{37+3\sqrt{6}}{\left(1-4\right)^{2}}
Factor 54=3^{2}\times 6. Rewrite the square root of the product \sqrt{3^{2}\times 6} as the product of square roots \sqrt{3^{2}}\sqrt{6}. Take the square root of 3^{2}.
\frac{37+3\sqrt{6}}{\left(-3\right)^{2}}
Subtract 4 from 1 to get -3.
\frac{37+3\sqrt{6}}{9}
Calculate -3 to the power of 2 and get 9.