Solve 35*4^3/5*(3-0,5

$$\frac { 35 \times 4 ^ { 3 } } { 5 \times ( 3 - 0,5 }$$

Evaluate

$$179,2$$

Solution Steps

Cancel out 5 in both numerator and denominator.

$$\frac{7\times 4^{3}}{3-0,5}$$

Calculate 4 to the power of 3 and get 64.

$$\frac{7\times 64}{3-0,5}$$

Multiply 7 and 64 to get 448.

$$\frac{448}{3-0,5}$$

Subtract 0,5 from 3 to get 2,5.

$$\frac{448}{2,5}$$

Expand \frac{448}{2,5} by multiplying both numerator and the denominator by 10.

$$\frac{4480}{25}$$

Reduce the fraction \frac{4480}{25} to lowest terms by extracting and canceling out 5.

$$\frac{896}{5}$$

Factor

$$\frac{7 \cdot 2 ^ {7}}{5} = 179\frac{1}{5} = 179.2$$