Solve 33/2^8-6/2^9

$$\frac { 33 } { 2 ^ { 8 } } - \frac { 6 } { 2 ^ { 9 } }$$

Evaluate

$$\frac{15}{128}=0.1171875$$

Solution Steps

Calculate 2 to the power of 8 and get 256.

$$\frac{33}{256}-\frac{6}{2^{9}}$$

Calculate 2 to the power of 9 and get 512.

$$\frac{33}{256}-\frac{6}{512}$$

Reduce the fraction \frac{6}{512} to lowest terms by extracting and canceling out 2.

$$\frac{33}{256}-\frac{3}{256}$$

Since \frac{33}{256} and \frac{3}{256} have the same denominator, subtract them by subtracting their numerators.

$$\frac{33-3}{256}$$

Subtract 3 from 33 to get 30.

$$\frac{30}{256}$$

Reduce the fraction \frac{30}{256} to lowest terms by extracting and canceling out 2.

$$\frac{15}{128}$$

Factor

$$\frac{3 \cdot 5}{2 ^ {7}} = 0.1171875$$