Solve 32/81+8/27*2+8/81*3+4/81

$$\frac { 32 } { 81 } + \frac { 8 } { 27 } \times 2 + \frac { 8 } { 81 } \times 3 + \frac { 4 } { 81 }$$

Evaluate

$$\frac{4}{3}\approx 1.333333333$$

Solution Steps

Express \frac{8}{27}\times 2 as a single fraction.

$$\frac{32}{81}+\frac{8\times 2}{27}+\frac{8}{81}\times 3+\frac{4}{81}$$

Multiply 8 and 2 to get 16.

$$\frac{32}{81}+\frac{16}{27}+\frac{8}{81}\times 3+\frac{4}{81}$$

Least common multiple of 81 and 27 is 81. Convert \frac{32}{81} and \frac{16}{27} to fractions with denominator 81.

$$\frac{32}{81}+\frac{48}{81}+\frac{8}{81}\times 3+\frac{4}{81}$$

Since \frac{32}{81} and \frac{48}{81} have the same denominator, add them by adding their numerators.

$$\frac{32+48}{81}+\frac{8}{81}\times 3+\frac{4}{81}$$

Add 32 and 48 to get 80.

$$\frac{80}{81}+\frac{8}{81}\times 3+\frac{4}{81}$$

Express \frac{8}{81}\times 3 as a single fraction.

$$\frac{80}{81}+\frac{8\times 3}{81}+\frac{4}{81}$$

Multiply 8 and 3 to get 24.

$$\frac{80}{81}+\frac{24}{81}+\frac{4}{81}$$

Since \frac{80}{81} and \frac{24}{81} have the same denominator, add them by adding their numerators.

$$\frac{80+24}{81}+\frac{4}{81}$$

Add 80 and 24 to get 104.

$$\frac{104}{81}+\frac{4}{81}$$

Since \frac{104}{81} and \frac{4}{81} have the same denominator, add them by adding their numerators.

$$\frac{104+4}{81}$$

Add 104 and 4 to get 108.

$$\frac{108}{81}$$

Reduce the fraction \frac{108}{81} to lowest terms by extracting and canceling out 27.

$$\frac{4}{3}$$

Factor

$$\frac{2 ^ {2}}{3} = 1\frac{1}{3} = 1.3333333333333333$$