Solve 3028/2019+1/2019^2+2*2019

$$\frac { 3028 } { 2019 } + \frac { 1 } { 2019 ^ { 2 } + 2 \times 2019 }$$

Evaluate

$$\frac{3031}{2021}\approx 1.499752598$$

Solution Steps

Calculate 2019 to the power of 2 and get 4076361.

$$\frac{3028}{2019}+\frac{1}{4076361+2\times 2019}$$

Multiply 2 and 2019 to get 4038.

$$\frac{3028}{2019}+\frac{1}{4076361+4038}$$

Add 4076361 and 4038 to get 4080399.

$$\frac{3028}{2019}+\frac{1}{4080399}$$

Least common multiple of 2019 and 4080399 is 4080399. Convert \frac{3028}{2019} and \frac{1}{4080399} to fractions with denominator 4080399.

$$\frac{6119588}{4080399}+\frac{1}{4080399}$$

Since \frac{6119588}{4080399} and \frac{1}{4080399} have the same denominator, add them by adding their numerators.

$$\frac{6119588+1}{4080399}$$

Add 6119588 and 1 to get 6119589.

$$\frac{6119589}{4080399}$$

Reduce the fraction \frac{6119589}{4080399} to lowest terms by extracting and canceling out 2019.

$$\frac{3031}{2021}$$

Factor

$$\frac{7 \cdot 433}{43 \cdot 47} = 1\frac{1010}{2021} = 1.499752597723899$$