Solve 30x/100+12/100(600)>15/100(x+600)

$$\frac { 30 x } { 100 } + \frac { 12 } { 100 } ( 600 ) > \frac { 15 } { 100 } ( x + 600 )$$

Solve for x

$$x>120$$

Solution Steps

Multiply both sides of the equation by 100. Since 100 is positive, the inequality direction remains the same.

$$30x+12\times 600>15\left(x+600\right)$$

Multiply 12 and 600 to get 7200.

$$30x+7200>15\left(x+600\right)$$

Use the distributive property to multiply 15 by x+600.

$$30x+7200>15x+9000$$

Subtract 15x from both sides.

$$30x+7200-15x>9000$$

Combine 30x and -15x to get 15x.

$$15x+7200>9000$$

Subtract 7200 from both sides.

$$15x>9000-7200$$

Subtract 7200 from 9000 to get 1800.

$$15x>1800$$

Divide both sides by 15. Since 15 is positive, the inequality direction remains the same.

$$x>\frac{1800}{15}$$

Divide 1800 by 15 to get 120.

$$x>120$$