Solve frac{30^2*sqrt[3]{35}}{x}+32=809.9

$$\frac { 30 ^ { 2 } \times \sqrt[ 3 ] { 35 } } { x } + 32 = 809.9$$

Solve for x

$$x = \frac{3000 \sqrt[3]{35}}{2593} \approx 3.78449631$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.

$$30^{2}\sqrt[3]{35}+x\times 32=809.9x$$

Calculate 30 to the power of 2 and get 900.

$$900\sqrt[3]{35}+x\times 32=809.9x$$

Subtract 809.9x from both sides.

$$900\sqrt[3]{35}+x\times 32-809.9x=0$$

Combine x\times 32 and -809.9x to get -777.9x.

$$900\sqrt[3]{35}-777.9x=0$$

Subtract 900\sqrt[3]{35} from both sides. Anything subtracted from zero gives its negation.

$$-777.9x=-900\sqrt[3]{35}$$

Divide both sides of the equation by -777.9, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-777.9x}{-777.9}=-\frac{900\sqrt[3]{35}}{-777.9}$$

Dividing by -777.9 undoes the multiplication by -777.9.

$$x=-\frac{900\sqrt[3]{35}}{-777.9}$$

Divide -900\sqrt[3]{35} by -777.9 by multiplying -900\sqrt[3]{35} by the reciprocal of -777.9.

$$x=\frac{3000\sqrt[3]{35}}{2593}$$