Solve for y
y=-8
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-5\left(3y+4\right)+10\left(3y-1\right)\times \frac{2}{5}=0
Variable y cannot be equal to \frac{1}{3} since division by zero is not defined. Multiply both sides of the equation by 10\left(3y-1\right), the least common multiple of 2-6y,5.
-15y-20+10\left(3y-1\right)\times \frac{2}{5}=0
Use the distributive property to multiply -5 by 3y+4.
-15y-20+4\left(3y-1\right)=0
Multiply 10 and \frac{2}{5} to get 4.
-15y-20+12y-4=0
Use the distributive property to multiply 4 by 3y-1.
-3y-20-4=0
Combine -15y and 12y to get -3y.
-3y-24=0
Subtract 4 from -20 to get -24.
-3y=24
Add 24 to both sides. Anything plus zero gives itself.
y=\frac{24}{-3}
Divide both sides by -3.
y=-8
Divide 24 by -3 to get -8.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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