Solve 3xy^4/x^3*1/xy^3

$$\frac { 3 x y ^ { 4 } } { x ^ { 3 } } \times \frac { 1 } { x y ^ { 3 } }$$

Evaluate

$$\frac{3y}{x^{3}}$$

Solution Steps

Cancel out x in both numerator and denominator.

$$\frac{3y^{4}}{x^{2}}\times \frac{1}{xy^{3}}$$

Multiply \frac{3y^{4}}{x^{2}} times \frac{1}{xy^{3}} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3y^{4}}{x^{2}xy^{3}}$$

Cancel out y^{3} in both numerator and denominator.

$$\frac{3y}{xx^{2}}$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$\frac{3y}{x^{3}}$$

Differentiate w.r.t. x

$$-\frac{9y}{x^{4}}$$