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\frac{3x-8-x+8}{4x}
Since \frac{3x-8}{4x} and \frac{-x+8}{4x} have the same denominator, add them by adding their numerators.
\frac{2x}{4x}
Combine like terms in 3x-8-x+8.
\frac{1}{2}
Cancel out 2x in both numerator and denominator.