Solve 3x-4/-4x+-2x+4/-4x

$$\frac { 3 x - 4 } { - 4 x } + \frac { - 2 x + 4 } { - 4 x }$$

Evaluate

$$-\frac{1}{4}=-0.25$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{-2x+4}{-4x}.

$$\frac{3x-4}{-4x}+\frac{2\left(-x+2\right)}{-4x}$$

Cancel out 2 in both numerator and denominator.

$$\frac{3x-4}{-4x}+\frac{-x+2}{-2x}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of -4x and -2x is 4x. Multiply \frac{3x-4}{-4x} times \frac{-1}{-1}. Multiply \frac{-x+2}{-2x} times \frac{-2}{-2}.

$$\frac{-\left(3x-4\right)}{4x}+\frac{-2\left(-x+2\right)}{4x}$$

Since \frac{-\left(3x-4\right)}{4x} and \frac{-2\left(-x+2\right)}{4x} have the same denominator, add them by adding their numerators.

$$\frac{-\left(3x-4\right)-2\left(-x+2\right)}{4x}$$

Do the multiplications in -\left(3x-4\right)-2\left(-x+2\right).

$$\frac{-3x+4+2x-4}{4x}$$

Combine like terms in -3x+4+2x-4.

$$\frac{-x}{4x}$$

Cancel out x in both numerator and denominator.

$$\frac{-1}{4}$$

Fraction \frac{-1}{4} can be rewritten as -\frac{1}{4} by extracting the negative sign.

$$-\frac{1}{4}$$

Factor

$$-\frac{1}{4} = -0.25$$