Solve 3x/2xx=3x+2y

$$\frac { 3 x } { 2 x } x = 3 x + 2 y$$

Solve for y

$$y=-\frac{3x}{4}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2x.

$$3xx=3x\times 2x+2y\times 2x$$

Multiply x and x to get x^{2}.

$$3x^{2}=3x\times 2x+2y\times 2x$$

Multiply x and x to get x^{2}.

$$3x^{2}=3x^{2}\times 2+2y\times 2x$$

Multiply 3 and 2 to get 6.

$$3x^{2}=6x^{2}+2y\times 2x$$

Multiply 2 and 2 to get 4.

$$3x^{2}=6x^{2}+4yx$$

Swap sides so that all variable terms are on the left hand side.

$$6x^{2}+4yx=3x^{2}$$

Subtract 6x^{2} from both sides.

$$4yx=3x^{2}-6x^{2}$$

Combine 3x^{2} and -6x^{2} to get -3x^{2}.

$$4yx=-3x^{2}$$

The equation is in standard form.

$$4xy=-3x^{2}$$

Divide both sides by 4x.

$$\frac{4xy}{4x}=-\frac{3x^{2}}{4x}$$

Dividing by 4x undoes the multiplication by 4x.

$$y=-\frac{3x^{2}}{4x}$$

Divide -3x^{2} by 4x.

$$y=-\frac{3x}{4}$$

Solve for x

$$x=-\frac{4y}{3}$$

$$y\neq 0$$