Solve 3x^3-9x^2/x-3*3x+18/3x^3+18x^2

$$\frac { 3 x ^ { 3 } - 9 x ^ { 2 } } { x - 3 } \cdot \frac { 3 x + 18 } { 3 x ^ { 3 } + 18 x ^ { 2 } }$$

Evaluate

$$3$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{3x^{3}-9x^{2}}{x-3}.

$$\frac{3\left(x-3\right)x^{2}}{x-3}\times \frac{3x+18}{3x^{3}+18x^{2}}$$

Cancel out x-3 in both numerator and denominator.

$$3x^{2}\times \frac{3x+18}{3x^{3}+18x^{2}}$$

Factor the expressions that are not already factored in \frac{3x+18}{3x^{3}+18x^{2}}.

$$3x^{2}\times \frac{3\left(x+6\right)}{3\left(x+6\right)x^{2}}$$

Cancel out 3\left(x+6\right) in both numerator and denominator.

$$3x^{2}\times \frac{1}{x^{2}}$$

Express 3\times \frac{1}{x^{2}} as a single fraction.

$$\frac{3}{x^{2}}x^{2}$$

Cancel out x^{2} and x^{2}.

$$3$$

Factor

$$3$$