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3x^{2}-\frac{5\times 2+1}{2}=0
Variable x cannot be equal to any of the values -2,9 since division by zero is not defined. Multiply both sides of the equation by \left(x-9\right)\left(x+2\right).
3x^{2}-\frac{10+1}{2}=0
Multiply 5 and 2 to get 10.
3x^{2}-\frac{11}{2}=0
Add 10 and 1 to get 11.
3x^{2}=\frac{11}{2}
Add \frac{11}{2} to both sides. Anything plus zero gives itself.
x^{2}=\frac{\frac{11}{2}}{3}
Divide both sides by 3.
x^{2}=\frac{11}{2\times 3}
Express \frac{\frac{11}{2}}{3} as a single fraction.
x^{2}=\frac{11}{6}
Multiply 2 and 3 to get 6.
x=\frac{\sqrt{66}}{6} x=-\frac{\sqrt{66}}{6}
Take the square root of both sides of the equation.
3x^{2}-\frac{5\times 2+1}{2}=0
Variable x cannot be equal to any of the values -2,9 since division by zero is not defined. Multiply both sides of the equation by \left(x-9\right)\left(x+2\right).
3x^{2}-\frac{10+1}{2}=0
Multiply 5 and 2 to get 10.
3x^{2}-\frac{11}{2}=0
Add 10 and 1 to get 11.
x=\frac{0±\sqrt{0^{2}-4\times 3\left(-\frac{11}{2}\right)}}{2\times 3}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, 0 for b, and -\frac{11}{2} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 3\left(-\frac{11}{2}\right)}}{2\times 3}
Square 0.
x=\frac{0±\sqrt{-12\left(-\frac{11}{2}\right)}}{2\times 3}
Multiply -4 times 3.
x=\frac{0±\sqrt{66}}{2\times 3}
Multiply -12 times -\frac{11}{2}.
x=\frac{0±\sqrt{66}}{6}
Multiply 2 times 3.
x=\frac{\sqrt{66}}{6}
Now solve the equation x=\frac{0±\sqrt{66}}{6} when ± is plus.
x=-\frac{\sqrt{66}}{6}
Now solve the equation x=\frac{0±\sqrt{66}}{6} when ± is minus.
x=\frac{\sqrt{66}}{6} x=-\frac{\sqrt{66}}{6}
The equation is now solved.