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\frac{\left(3x^{2}-11x-4\right)\times 6}{\left(2x-8\right)\left(9x+3\right)}
Divide \frac{3x^{2}-11x-4}{2x-8} by \frac{9x+3}{6} by multiplying \frac{3x^{2}-11x-4}{2x-8} by the reciprocal of \frac{9x+3}{6}.
\frac{6\left(x-4\right)\left(3x+1\right)}{2\times 3\left(x-4\right)\left(3x+1\right)}
Factor the expressions that are not already factored.
1
Cancel out 2\times 3\left(x-4\right)\left(3x+1\right) in both numerator and denominator.
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