Solve 3x+9/4=x

$$\frac { 3 x + 9 } { 4 } = x$$

Solve for x

$$x=9$$

Steps for Solving Linear Equation

Divide each term of 3x+9 by 4 to get \frac{3}{4}x+\frac{9}{4}.

$$\frac{3}{4}x+\frac{9}{4}=x$$

Subtract x from both sides.

$$\frac{3}{4}x+\frac{9}{4}-x=0$$

Combine \frac{3}{4}x and -x to get -\frac{1}{4}x.

$$-\frac{1}{4}x+\frac{9}{4}=0$$

Subtract \frac{9}{4} from both sides. Anything subtracted from zero gives its negation.

$$-\frac{1}{4}x=-\frac{9}{4}$$

Multiply both sides by -4, the reciprocal of -\frac{1}{4}.

$$x=-\frac{9}{4}\left(-4\right)$$

Express -\frac{9}{4}\left(-4\right) as a single fraction.

$$x=\frac{-9\left(-4\right)}{4}$$

Multiply -9 and -4 to get 36.

$$x=\frac{36}{4}$$

Divide 36 by 4 to get 9.

$$x=9$$