Solve 3x+6/4leq3x

$$\frac { 3 x + 6 } { 4 } \leq 3 x$$

Solve for x

$$x\geq \frac{2}{3}$$

Solution Steps

Multiply both sides of the equation by 4. Since 4 is positive, the inequality direction remains the same.

$$3x+6\leq 12x$$

Subtract 12x from both sides.

$$3x+6-12x\leq 0$$

Combine 3x and -12x to get -9x.

$$-9x+6\leq 0$$

Subtract 6 from both sides. Anything subtracted from zero gives its negation.

$$-9x\leq -6$$

Divide both sides by -9. Since -9 is negative, the inequality direction is changed.

$$x\geq \frac{-6}{-9}$$

Reduce the fraction \frac{-6}{-9} to lowest terms by extracting and canceling out -3.

$$x\geq \frac{2}{3}$$