Solve 3x+2x/49sqrt{3}=7

$$\frac { 3 x + 2 x } { 49 \sqrt { 3 } } = 7$$

Solve for x

$$x = \frac{343 \sqrt{3}}{5} \approx 118.818685399$$

Steps for Solving Linear Equation

Combine 3x and 2x to get 5x.

$$\frac{5x}{49\sqrt{3}}=7$$

Rationalize the denominator of \frac{5x}{49\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.

$$\frac{5x\sqrt{3}}{49\left(\sqrt{3}\right)^{2}}=7$$

The square of \sqrt{3} is 3.

$$\frac{5x\sqrt{3}}{49\times 3}=7$$

Multiply 49 and 3 to get 147.

$$\frac{5x\sqrt{3}}{147}=7$$

Multiply both sides by 147.

$$5x\sqrt{3}=7\times 147$$

Multiply 7 and 147 to get 1029.

$$5x\sqrt{3}=1029$$

The equation is in standard form.

$$5\sqrt{3}x=1029$$

Divide both sides by 5\sqrt{3}.

$$\frac{5\sqrt{3}x}{5\sqrt{3}}=\frac{1029}{5\sqrt{3}}$$

Dividing by 5\sqrt{3} undoes the multiplication by 5\sqrt{3}.

$$x=\frac{1029}{5\sqrt{3}}$$

Divide 1029 by 5\sqrt{3}.

$$x=\frac{343\sqrt{3}}{5}$$